# Leetcode Solving the “Container With Most Water” LeetCode Problem in JavaScript

The “Container With Most Water” problem is a classic algorithmic challenge that can be found on LeetCode. In this blog post, we’ll explore an efficient solution to this problem using JavaScript.

Problem Statement:

You are given an integer array `height`

of length `n`

. There are `n`

vertical lines drawn such that the two endpoints of the `ith`

line are `(i, 0)`

and `(i, height[i])`

.

Find two lines that together with the x-axis form a container, such that the container contains the most water.

Return *the maximum amount of water a container can store*.

**Notice** that you may not slant the container.

**Example 1:**

**Input:** height = [1,8,6,2,5,4,8,3,7]
**Output:** 49
**Explanation:** The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

**Example 2:**

**Input:** height = [1,1]
**Output:** 1

**Constraints:**

`n == height.length`

`2 <= n <= 105`

`0 <= height[i] <= 104`

### 1. Understanding the Problem:

The problem statement requires us to find the two lines on a 2D plane that form a container with the most water. The input is an array of non-negative integers, where each integer represents the height of a vertical line at a particular index. Our task is to determine the maximum amount of water that can be trapped by the container formed by any two lines from the array.

### 2. Approach:

To solve this problem efficiently, we can **use the two-pointer technique**. We’ll start with two pointers, one at the beginning of the array and the other at the end. We’ll calculate the area between the lines represented by these two pointers and keep track of the maximum area found so far. Then, we’ll move the pointer with the smaller height inward, as moving the pointer with the larger height wouldn’t yield a larger area.

3. JavaScript Solution:

` `

```
function maxArea(height) {
let left = 0;
let right = height.length - 1;
let maxArea = 0;
while (left < right) {
const currentHeight = Math.min(height[left], height[right]);
const currentWidth = right - left;
const area = currentHeight * currentWidth;
maxArea = Math.max(maxArea, area);
if (height[left] < height[right]) {
left++;
} else {
right--;
}
}
return maxArea;
}
```

#### 4. Time and Space Complexity:

The two-pointer approach reduces the time complexity to O(n), where n is the number of elements in the height array, as we iterate through the array only once. The space complexity is O(1) since we use a constant amount of extra space.

#### Conclusion:

In this blog post, we discussed the “Container With Most Water” problem from LeetCode and provided an efficient JavaScript solution using the two-pointer technique. By incorporating proper SEO techniques, we aim to make this blog post more discoverable and helpful for developers seeking a solution to this classic algorithmic problem. Happy coding!

I simply could not leave your web site prior to suggesting that I extremely

enjoyed the usual information an individual supply to your guests?

Is going to be again continuously in order to check out new

posts

Have you ever considered about including a little bit more than just

your articles? I mean, what you say is important and all.

Nevertheless just imagine if you added some great pictures or videos to give your posts more,

“pop”! Your content is excellent but with pics and videos, this site could undeniably

be one of the most beneficial in its niche.

Wonderful blog!

You actually make it seem so easy with your presentation but I find this topic to be actually something which I think I would never understand.

It seems too complex and extremely broad for me. I’m looking forward

for your next post, I will try to get the hang of it!

You really make it seem so easy with your presentation but I find this

topic to be really something that I believe I’d never understand.

It sort of feels too complex and extremely extensive for me.

I am having a look forward to your next publish, I’ll try to get the dangle of

it!

Do you mind if I quote a few of your articles as long as I provide credit and sources back to your webpage?

My website is in the very same niche as yours and my visitors would definitely benefit from some of the information you provide here.

Please let me know if this ok with you. Thank you!

It’s not my first time to visit this web page, i am browsing

this website dailly and obtain pleasant data from here all the time.

This paragraph will assist the internet viewers for setting

up new web site or even a weblog from start to end.

Hi i am kavin, its my first time to commenting anywhere, when i read this

piece of writing i thought i could also create comment due

to this good paragraph.

Howdy would you mind letting me know which hosting company you’re utilizing?

I’ve loaded your blog in 3 different internet browsers and I

must say this blog loads a lot quicker then most. Can you

recommend a good web hosting provider at a reasonable price?

Many thanks, I appreciate it!

Thanks a lot for sharing this with all folks you really realize what

you are speaking about! Bookmarked. Kindly also seek advice from my web site =).

We may have a hyperlink trade agreement among us

Hello there, just became aware of your blog through Google, and found that it’s

really informative. I am going to watch out for brussels. I’ll appreciate if you continue this in future.

Numerous people will be benefited from your writing.

Cheers! Najlepsze escape roomy

I’m not that much of a online reader to be honest but

your sites really nice, keep it up! I’ll go ahead and bookmark your website to come back down the road.

Many thanks

I have not checked in here for some time since I thought it was getting boring, but the last few posts are good quality so I guess I?¦ll add you back to my everyday bloglist. You deserve it my friend 🙂