The problem, as stated on LeetCode, is to traverse a given m x n matrix in a spiral order and return all the elements in that order.
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
Approach and Algorithm
To solve this problem, we will simulate the process of spiraling through the matrix. We will use four pointers to represent the boundaries of the current spiral. As we move through each spiral layer, we will collect the elements in the order specified.
The algorithm can be summarized as follows:
- Initialize four pointers top, bottom, left, and right to represent the boundaries of the current spiral.
- Traverse the matrix in a spiral order while updating these pointers and collecting the elements.
- Repeat until all elements in the matrix have been processed.
Time and Space Complexity Analysis
Let’s analyze the time and space complexity of our solution.
The solution iterates through the entire matrix once, visiting each cell exactly once. Therefore, the time complexity is O(m * n), where m is the number of rows, and n is the number of columns in the matrix.
The space complexity is O(m * n) as well. The result array stores all the elements in the matrix.
Solving problems like these can enhance your problem-solving skills and improve your coding abilities. We hope this article was helpful to you, and happy coding! Keep practicing, and you’ll become a master of algorithmic challenges in no time!
If you have any questions or suggestions, feel free to leave a comment below.